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18d^2+45d+25=0
a = 18; b = 45; c = +25;
Δ = b2-4ac
Δ = 452-4·18·25
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-15}{2*18}=\frac{-60}{36} =-1+2/3 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+15}{2*18}=\frac{-30}{36} =-5/6 $
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